If the time discrepancy is 0.5 nanoseconds, what is the distance error in meters?

Study for the Geodesy Refresher Exam. Prepare with multiple choice questions, hints, and explanations. Ace your exam with confidence!

Multiple Choice

If the time discrepancy is 0.5 nanoseconds, what is the distance error in meters?

Explanation:
Distance error from a time discrepancy is found by multiplying the signal’s travel speed by the time error. For light-speed signals, distance error = c × Δt. With Δt = 0.5 nanoseconds = 0.5 × 10^-9 s and c ≈ 299,792,458 m/s, the product is about 0.1499 meters, i.e., roughly 0.15 m. So the distance error is about 0.15 meters. The other options would require larger time errors (for example, 0.5 m corresponds to about 1.67 ns), which isn’t the given discrepancy.

Distance error from a time discrepancy is found by multiplying the signal’s travel speed by the time error. For light-speed signals, distance error = c × Δt. With Δt = 0.5 nanoseconds = 0.5 × 10^-9 s and c ≈ 299,792,458 m/s, the product is about 0.1499 meters, i.e., roughly 0.15 m. So the distance error is about 0.15 meters. The other options would require larger time errors (for example, 0.5 m corresponds to about 1.67 ns), which isn’t the given discrepancy.

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